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A bar magnet of length 0.2m placed in a ...

A bar magnet of length 0.2m placed in a uniform magnetic field of induction `15 Wbm^(-2)`, with its axis at `30^(@)` to the field experience a couple of 7.5 N-m. Find the pole strength of the bar magnet.

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To find the pole strength of the bar magnet, we can use the formula for the torque (couple) experienced by a bar magnet in a magnetic field. The torque (τ) is given by the equation: \[ \tau = m \cdot B \cdot L \cdot \sin(\theta) \] Where: - \( \tau \) = Torque (N·m) ...
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AAKASH SERIES-MAGNETISM-PROBLEMS (LEVEL-II)
  1. The force between two poles is reduced to P newton, when their origina...

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  2. The field intensities of two points on the axial line of a bar magnet ...

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  3. The magnetic induction on the equatorial line of a short magnet at dis...

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  4. A short bar magnet produces magnetic fields of equal induction at two ...

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  5. Calculate the moment of couple required to keep a bar magnet of magnet...

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  6. A bar magnet of length 0.2m placed in a uniform magnetic field of indu...

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  7. A bar magnet of magnetic moment 2.0 A m^2 is free to rotate about a ve...

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  8. A magnet of magnetic moment 5Am^(2) is freely suspended in a uniform m...

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  9. A very long magnet of pole strength 4A-m is placed vertically with its...

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  10. A short bar magnet is placed with its north pole pointing north. The n...

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  11. A magnet is suspended in such a way that it oscillates in the horizont...

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  12. A magnet makes 10 oscillations per minute at a place where the angle o...

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  13. A magnetic needle is free to rotate in a vertical plane which makes an...

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  14. The work done in rotating a magnet from the direction of uniform field...

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  15. A freely suspended short magnet makes 20 oscillations per minute in th...

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  16. In an uniform field the magnetic needle completes 10 oscillations in 9...

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