A magnet of magnetic moment `5Am^(2)` is freely suspended in a uniform magnetic field of strength 2T. Find the work done in rotating the magnet through an angle of `60^(@)`.

Explanation

To find the work done in rotating a magnet through an angle in a magnetic field, we can use the formula:

\[ W = mB \left( \cos \theta_1 - \cos \theta_2 \right) \]

Where:
- \( W \) is the work done,
- \( m \) is the magnetic moment,
- \( B \) is the magnetic field strength,
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