A magnet makes 10 oscillations per minute at a place where the angle of dip is `45^(@)` and the resultant earth's field is 0.4 gauss. Calculate the number of oscillations made per second by the same magnet at another place where the angle of dip is `60^(@)` and the resultant earth's field is 0.5 gauss.

Explanation

To solve the problem, we will use the formula for the time period of oscillation of a magnet in a magnetic field, which is given by:

\[ T = 2\pi \sqrt{\frac{I}{mB_H}} \]

where:
- \( T \) is the time period of oscillation,
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