How many times a particle will reach maximum displacement during the time taken by the wave to advance by one wavelength?

An harmonic wave has been set up on a very long string which travels along the length of the string. The wave has a frequency of 50 Hz, amplitude 1 cm and wavelength 0.5 m. find (a) the time taken by the wave to travel a distance of 8 m along the length of string (b) the time taken by a point on the string to travel a distance of 8 m, once the wave has reached the point and sets it into motion (c ) also. consider the above case when the amplitude gets doubled

velocity time graph of a particle is shown in figure. Find displacement of the particle.

A simple harmonic progressive wave in a gas has a particle displacement of y=a at time t=T//4 at the orgin of the wave and a particle velocity of y =v at the same instant but at a distance x=lambda//4 from the orgin where T and lambda are the periodic time and wavelength of the wave respectively. then for this wave.

A particle is projected from surface of the inclined plane with speed u and at an angle theta with the horizontal. After some time the particle collides elastically with the smooth fixed inclined plane for the first time and subsequently moves in vertical direction. Starting from projection, find the time taken by the particle to reach maximum height. (Neglect time of collision).

From a tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle, to hit the ground, is n times that taken by it to reach the highest point of its path. The relation between H, u and n is

From a tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle, to hit the ground, is n times that taken by it to reach the highest point of its path. The relation between H, u and n is

From a tower of height H, a particle is thrown vertically up with a speed V. The time taken by the particle to hit the ground 3 tiem that taken by it to reach the highest point of is path . Then find H.

For ground to ground projectile, time take by a particle to ge point O to point C is T_(1) and during the same motion time taken by the particle to ge from A to B is T_(2) then height 'h' is :

If time taken by the projectile to reach Q is T , than PQ =