An аudio signal given by `e_(s) = 15 sin 2pi (200t)` modulates a carrier wave given by `e_(s) = 60 sin 2pi(100,000t)`. If calculate
Percent modulation

Explanation

a)Signla Amplitude ,B=15,Carrier amplitude,
A=60
`m=(B)/(A)=(15)/(10)=0.25`
`therefore ` Percentage modulation =`0.25xx100=25%`
b)By comparing the given equations of signal and carrier with their standard form
`e_(S)=E_(s)sin omega_(s)t=E_(S)sin2pi f_(S)t` and
`e_(C)=E_(C)sin omega_(C)t=E_(C)sin 2pif_(c)t`
We have signal frequency `f_(s)`=2000 Hz and carrier frequency `f_(C)`=100,00 Hz
The frequencies present in modulated wave
i) `f_(c)`=100,000 Hz=100kHz
ii) `f_(c)-f_(s)`=100,000-2000 =98 kHz
iii)`f_(c)+f_(s)`=100 kHz+2kHz=102 kHz
Therefore,frequency spectrum of modulated wave extends from 98 kHz to 102 kHz (This is called band width.)