The load current in the transmitting antenna of an unmodulated AM transmitter is 6 Amp. What will be the antenna current when modulation is `60%`.

Explanation

Total power carried by AM wave
`P_(T)=P_(C)(1+(m^(2))/(2))`…..(1)
Where `P_(C)` is the power of carrier componenet and m is the modulation factor.If R is the resistance ,`I_(m)` the antenna load current when modulation is 60% and `I_(C)` Is the antenna load current when unmodulated ,then
`(P_(T))/(P_(C))=(I_(m)^(2)R)/(I_(C)^(2)R)" "therefore 1+(m^(2))/(2)=(I_(m)^(2))/(I_(C)^(2))` using (1)
or `I_(m)=I_(C)sqrt({(1+(m^(2))/(2))})`
Given `I_(C)`=6Amp,m=0.6
6[1.086]=6.52 Amp.