A charge `4muC` is placed in an electric field of magnitude 8 N/C. Find the force on it.

Answer

To solve the problem of finding the force on a charge placed in an electric field, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values**:
- Charge, \( q = 4 \, \mu C = 4 \times 10^{-6} \, C \)
- Electric Field, \( E = 8 \, N/C \)

2. **Use the Formula for Force**:
The force \( F \) experienced by a charge \( q \) in an electric field \( E \) is given by the formula:
\[ F = q \times E \]

3. **Substitute the Values into the Formula**:
Substitute the values of \( q \) and \( E \) into the formula:
\[ F = (4 \times 10^{-6} \, C) \times (8 \, N/C) \]

4. **Calculate the Force**:
Perform the multiplication:
\[ F = 32 \times 10^{-6} \, N \]

5. **Express the Final Answer**:
The final answer can be expressed in standard form:
\[ F = 3.2 \times 10^{-5} \, N \]

### Final Answer:
The force on the charge is \( 3.2 \times 10^{-5} \, N \).

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