A charge 2C is moved between two points where potentials are 17 and 8V respectively. What is the work done in moving the charge.

Answer

To find the work done in moving a charge between two points with different electric potentials, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Charge (Q) = 2 C
- Initial potential (V1) = 17 V
- Final potential (V2) = 8 V

2. **Calculate the Change in Potential (ΔV):**
- The change in potential (ΔV) is given by the formula:
\[ \Delta V = V_f - V_i \]
- Here, \(V_f\) is the final potential (V2) and \(V_i\) is the initial potential (V1).
- Substituting the values:
\[ \Delta V = V2 - V1 = 8 V - 17 V = -9 V \]

3. **Use the Work Done Formula:**
- The work done (W) in moving a charge in an electric field is given by:
\[ W = Q \cdot \Delta V \]
- Substituting the values:
\[ W = 2 C \cdot (-9 V) \]

4. **Calculate the Work Done:**
- Now, calculate the work done:
\[ W = 2 \cdot (-9) = -18 \text{ Joules} \]

5. **Final Answer:**
- The work done in moving the charge is \(-18\) Joules.