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Two identical particles of mass m carry a charge Q each. Initially one is at rest on a smooth horizontal plane and the other is projected along the plane directly towards first particle from a large distance with speed v. The closest distance of approach be :

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The correct Answer is:
`(3q^(2)d)/(3q^(2)+4pi in_(0) m u^(2)d)`
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AAKASH SERIES-ELECTRIC FIELD AND POTENTIAL-PROBLEMS (LEVEL-II)
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