The temperature coefficient of resistance of platinum is `alpha=3.92xx10^(-3)K^(-1)` at `0^(@)C`. Find the temperature at which the increase in the resistance of platinum wire is `10%` of its value of `0^(@)C`.

Explanation

To solve the problem of finding the temperature at which the resistance of a platinum wire increases by 10% of its value at 0°C, we can follow these steps:

### Step 1: Understand the given data
- The temperature coefficient of resistance of platinum, \( \alpha = 3.92 \times 10^{-3} \, \text{K}^{-1} \).
- The increase in resistance is 10% of its initial value at 0°C.

### Step 2: Define the initial resistance
Let the initial resistance at 0°C be \( R_0 \).
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