In the given circuit , the two cells have no internal resistance. Calculate the potential difference across the `20 Omega` resistor .

Explanation

Applying Kirchoff.s law to loop PRQP :
60I + `20 I_1 = 4 " "….(1)`
For Loop PSRP : `200(I-I_1) - 20 I_1= 5 " "….(2)`
Solving (1) and (2) , `I_1 = (5)/(172) A`
`implies V_(20) = (5)/(172) xx 20 =(25)/(43) ` or 0.594 volt