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Find the value of R in fig. so that ther...

Find the value of R in fig. so that there is no current in the 15 `Omega` resistor

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This is the Wheatstone bridge with the galvanometer replaced by `15 Omega` resistor. The bridge is balanced because there is no current is 15 `Omega` resistor, hence,
`20//10 = 40//R`
`therefore R= (40 xx 10 Omega)/(20) = 20 Omega`
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