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Let two cells of e.m.f.'s E1 and E2 be c...

Let two cells of e.m.f.'s `E_1 and E_2` be connected in parallel in a circuit . Let `r_1 and r_2` be the internal resistances of the cells . Find the value of the current

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Resultant p.d. due to `E_1 and E_2 = E_1 - E_2`
Sum of internal resistance = `r_1 + r_2`
`therefore ` current `I =(E_1 - E_2)/((r_1 +r_2))`
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