A cell is e.m.f 2V and internal resistance `1 Omega` is connected to a potentiometer of length 1m and resistance `4 Omega` Calculate the potential drop per cm.

Explanation

e.m.f of cell E = 2V
Internal resistance of potentiometer wire R=` 4 Omega`
Potential drop `V= E((R)/(R+r)) = (2xx4)/(4+1) = 1.6 V`
Potential drop per cm
`=V/l = (1.6)/(100) = 1.6 xx 10^(-2) ` volt/cm.