A circuit having resistor of 2 mega-ohm and capacitor of `1 muF` is placed in series with a battery of 2 volt. Find the time after which the charge reaches 86.4% of its maximum value.

Explanation

To solve the problem step by step, we will follow the process of analyzing the charging of a capacitor in an RC circuit.

### Step 1: Identify the given values
- Resistance \( R = 2 \, \text{M}\Omega = 2 \times 10^6 \, \Omega \)
- Capacitance \( C = 1 \, \mu\text{F} = 1 \times 10^{-6} \, \text{F} \)
- Voltage \( V = 2 \, \text{V} \)

### Step 2: Calculate the time constant \( \tau \)
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