A capacitor is being charged through a resistance of 3 mega ohm. If it reaches 75% of its final potential in 0.5 sec, find its capacitance.

Explanation

To solve the problem of finding the capacitance of a capacitor being charged through a resistance of 3 mega ohms, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Given Values:**
- Resistance (R) = 3 mega ohms = \(3 \times 10^6 \, \Omega\)
- Time (t) = 0.5 seconds
- Voltage fraction (V/V0) = 0.75 (75% of the final potential)
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