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A capacitor of 1 muF and resistance 82 k...

A capacitor of `1 muF` and resistance `82 kOmega` are connected is series with a d.c. source of 100 volt. Calculate the magnitude of energy and the time in which energy stored in the capacitor will reach half of its maximum value.

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To solve the problem step by step, we will break it down into two parts: calculating the energy stored in the capacitor and determining the time at which the energy reaches half of its maximum value. ### Step 1: Calculate the Maximum Energy Stored in the Capacitor The formula for the energy stored in a capacitor is given by: \[ E = \frac{1}{2} C V^2 ...
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AAKASH SERIES-CURRENT ELECTRICITY-PROBLEMS (LEVEL-II)
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  3. At room temperature (27.0 .^(@)C) the resistance of a heating element ...

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  4. Determine the current in each branch of the network shown in figure.

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  5. A storage battery of emf 8.0 V and internal resistance 0.5 Omega is be...

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  6. Two wires of equal length, one of aluminium and the other of copper ha...

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  7. (a) Given n resistors each of resistance R, how will you combine them ...

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  8. Determine the equivalent resistance of networks shown in figures above

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  9. Given the resistances 2 Omega , 3 Omega , 4 Omega how will you combine...

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  10. The correct combination of three resistances 1Omega, 2Omega and 3Omega...

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  11. Given the resistances 1 Omega , 2 Omega , 3 Omega how will you combine...

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  12. (6//11) Omega

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  13. Figure 6.13 shows a 2.0 V potentiometer used for the determination of ...

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  16. A secondary cell after long use has an emf of 1.9 V and a large intern...

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  17. Determine the current drawn from a 12V supply with internal resistance...

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  18. Figure 6.36 shows a potentiometer with a cell of emf 2.0 V and interna...

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  19. Figure 6.36 shows a potentiometer with a cell of emf 2.0 V and interna...

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  20. Figure 6.36 shows a potentiometer with a cell of emf 2.0 V and interna...

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  21. Figure 6.36 shows a potentiometer with a cell of emf 2.0 V and interna...

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