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A battery of emf 2V and internal resista...

A battery of emf 2V and internal resistance `0.5(Omega)`is connected across a resistance 1.5(Ω). Find the current flow through battery ?

Text Solution

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In the first case `I = (1.5)/(5+25) = (1.5)/(30)` and `V=1.5 - ((15)/(30)) 5 = 1.5 - 0.25 = 1.25 V " "….(1)`
In the second case `i= (1.5)/(5+5) = (1.5)(10) and V=1.5 -((1.5)/(10))5 = 0.75 V " "….(2)`
The voltmetre reading is higher in the first case.
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