An equilateral glass prism is made of a material of refractive index 1.500. Find its angle of minimum deviation.

Explanation

`A=60^@,mu=1.5, delta_(min)=?`
Substituting in `mu=(sin((A+delta_(min))/2))/sin(A/2)`
`1.5=(sin(60^@+delta_(min))/2)/((sin 60^@/2))`
`1.5 sin 30^@ = sin ((60^@+ delta_(min))/2)`
`sin((60^@+ delta_(min))/2)=1.5 times0.5000=0.7500`
`(60^@+delta_(min))/2=48^@35.`
`60^@+ delta_(min)= 97^@10 implies delta_(min)=37^@.10`