A ray of light undergoes deviation of `30^@` when incident on an equilateral prism of refractive index `sqrt2.` what is the angle subtended by the ray inside the prism with the base of the prism?

Explanation

Here `delta=30^@ and A=60^@`
So if the prism had been in minimum deviation,
`mu= (sin[30^@+60^@]//2)/(sin (60^@//2))=sin 45^@/sin 30^@=1/sqrt2 times 2=sqrt2`
And as `mu` of the prism is given to be `sqrt2`

The prism is in the position implies that
`r_1=r_2=r=(A/2)=(60^@/2)=30^@`
Therefore, angle subtended by the ray inside the prism with the surface `AB(90^@-r)=(90^@-30^@)=60^@` and as base also subtends an angle of `60^@` with the face AB, the ray inside the prism in parallel to the base i.e., the angle subtended by the ray inside the prism with the base is zero.