Home
Class 11
PHYSICS
A far sighted person cannot focus distin...

A far sighted person cannot focus distinctly on objects closer than Im. What is the power of lens that will permit him to read from a distance of 40cm?

Text Solution

AI Generated Solution

To solve the problem step by step, we need to determine the power of the lens required for a far-sighted person to read from a distance of 40 cm. Here’s how we can approach it: ### Step 1: Understand the problem A far-sighted person has a near point of 1 meter (100 cm), meaning they cannot see objects clearly that are closer than this distance. We want to find the power of a lens that allows them to read at a distance of 40 cm (0.4 meters). ### Step 2: Identify the variables - Near point (D) = 1 m (100 cm) - Object distance (u) = -0.4 m (since the object is in front of the lens, we take it as negative) ...
Promotional Banner

Similar Questions

Explore conceptually related problems

A farsighted person cannot see objects placed closer to 50 cm. Find the power of the lens needed to see the objects at 20 cm.

A person cannot see objects clearly beyond 50.cm. The power of lens to correct the vision

A far sighted person cannot see object clearly al a distance less than 75 cm from his eyes. The power of the lens needed to read an object al 25 cm is

A short sighted person can see distinctly only those objects which lie between 10 cm and 100 cm from him. The power of the spectacle lens required to see a distant object is

A person cannot see objects clearly beyond 125 cm. The power of the lens to correct the vision is

A person cannot see distinctly object kept beyond 2 m. This defect can be corrected by using a lens of power

A nearsighted person cannot clearly see beyond 200 cm. Find the power of the lens needed to see objects at large distances.

The near point and far point of a person are 40cm and 250cm, respectively. Determine the power of lens he/she should use while reading a bool kept at distance 25cm away from it,

A nearsighted person cannot see beyond 25 cm. Assuming that the separation of the glass from the eye is 1 cm, find the power of lens needed to see distant objects.

In compound microscope the magnification is 95, and the distance of object from objective lens 1/3.8 cm and focal length of objective is ¼ cm. What is the magnification of eye pieces when final image is formed at least distance of distinct vision :