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A compound microscope has a magnifying p...

A compound microscope has a magnifying power 30. the focal length of its eyepiece is 5 cm. assuming the final image to be formed at least distance of distinct vision (25 cm), calculate the magnification produced by the objective.

Text Solution

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In case of compound microscope
`M=m_0 times m_e`…….(1)
And in case of final image at least distance of distinct vision
`m_e=[1+D/f.]`
So from eqs. (1) and (2)
`M=m_0[1+D/f]`
Here M=-30, D=25cm and `f_e=5cm`
So, `-30=m_0[1+25/5]` i.e., `m_0=(-30)/6=-5`
Negative sign implies that image formed by objective is inverted.
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