Home
Class 11
MATHS
In a DeltaABC, I is the incentre and AI ...

In a `Delta`ABC, I is the incentre and AI cuts BC at D. If B=(-1,2) C(9,7), AB = 14, AC =21 then find D.

Text Solution

AI Generated Solution

The correct Answer is:
To find the coordinates of point D where the angle bisector AI intersects side BC in triangle ABC, we can follow these steps: ### Step 1: Identify the coordinates of points B and C. Given: - B = (-1, 2) - C = (9, 7) ### Step 2: Calculate the lengths of sides AB and AC. We are given: - AB = 14 - AC = 21 ### Step 3: Determine the ratio in which point D divides line segment BC. According to the angle bisector theorem, the internal angle bisector divides the opposite side in the ratio of the lengths of the other two sides. Hence, we have: - Ratio of AB to AC = 14:21 = 2:3 ### Step 4: Use the section formula to find the coordinates of point D. The section formula states that if a point D divides the line segment joining points B(x1, y1) and C(x2, y2) in the ratio m:n, then the coordinates of D are given by: \[ D\left(\frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n}\right) \] Here, m = 2 and n = 3, and we have: - \(x_1 = -1\), \(y_1 = 2\) (coordinates of B) - \(x_2 = 9\), \(y_2 = 7\) (coordinates of C) Substituting the values into the formula: \[ D_x = \frac{2 \cdot 9 + 3 \cdot (-1)}{2 + 3} = \frac{18 - 3}{5} = \frac{15}{5} = 3 \] \[ D_y = \frac{2 \cdot 7 + 3 \cdot 2}{2 + 3} = \frac{14 + 6}{5} = \frac{20}{5} = 4 \] ### Step 5: Conclude the coordinates of point D. Thus, the coordinates of point D are: \[ D = (3, 4) \]
Promotional Banner

Similar Questions

Explore conceptually related problems

ABC is a triangle and the internal angle bisector of angle A cuts the side BC at D. If A=(3,-5), B(-3,3), C=(-1,-2) then find the length AD

In a /_\ A B C , A D is the bisector of /_A , meeting side B C at D . (i) If AB=10 cm , AC=14 cm and BC=6cm , find B D and D C (ii) If A C=4. 2 c m , D C=6c m and B C=10 c m , find A B . (iii) If A B=5. 6 c m , A C=6c m and D C=3c m , find B C .

In Delta ABC, the perependicular from A BC meets BC at D such that BD =7 cm and DC = 12 cm. Find the ratio of the areas of the triangles ABD and ADC.

ABC is a triangle right angled at C. If AB=25cm and AC=7cm, find BC.

In triangle ABC, P is mid-point of AB and Q is mid-point of AC. If AB = 9.6 cm, BC = 11 cm and AC = 11.2 , find the perimeter of the trapezium PBCQ.

In triangle ABC , angle B = 90 ^(@) , AB = 40 , AC + BC = 80 , Find : tan C .

If A:B = 2:7 and B:C = 9:13, find A:C.

In triangle ABC , angle B = 90 ^(@) , AB = 40 , AC + BC = 80 , Find : sin A

In triangle ABC , angle B = 90 ^(@) , AB = 40 , AC + BC = 80 , Find : cos A

If ABC is a triangle such that A=(1,2) and B=(5,5) with BC=9 and AC =12 units , then slope of altitude CD is (D is a point on BC)