In the given circuit, with steady current, the potential drop across the capacitor must be

Explanation

Apply Kirchhoff.s law to the closed mesh
ACDFA, `2V-I(2R)-I(R )-V=0` or
`V=3IR or I=(V )/(3R )`
Applying Kirchhoff.s law of the mesh ABEFA,
`V+V_(C )-IR-V=0` or
`V_(C )=IR=((V)/(3R))R=(V)/(3)`
`therefore" Potential difference across capacitor "V_(C )=(V )/(3)`