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particle of mass m, moving with velocity...

particle of mass m, moving with velocity 'u' makes head on collision with identical stationary particle, which is elastic. Theforce of interaction increases to maximum and then becomes zero in time 'T' as shown in graph. What is the maximum value `F_(0)` of interaction force ?

Text Solution

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Force reaches maximum value in `(T)/(2)`
time. The impulse of maximum force is, `= F_(0)xx(T)/(2)`
Since, impulse = Change in momentum, mu = `F_(0).(T)/(2)` i.e., `F_(0)=(2m u)/(T)`
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