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A boy of mass 60kg is standing over a pl...

A boy of mass `60kg` is standing over a platform of mass `40kg` placed over a smooth horizontal surface. He throws a stone of mass `1kg` with velocity `v=10m//s` at an angle of `45^@` with respect to the ground. Find the displacement of the platform (with boy) on the horizontal surface when the stone lands on the ground. Take `g=10m//s^2`.

Text Solution

Verified by Experts

`1.u cos 45^(@)=(60+40)v, v=(1)/(10sqrt(2))`
Time of light `= T_(f)=(2u sin theta)/(g)=sqrt(2)sec`.
`S = v xx T_(f)=0.1m`.
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