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An isolated particle of mass m is moving...

An isolated particle of mass `m` is moving in horizontal plane` xy` along the `x`-axis, at a certain height above the ground. It suddenly explodes into two fragment of masses `m//4` and `3m//4`. An instant later, the smaller fragment is at `y=+15` cm. The larger fragment at this instant is at

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As `vec(F)_(y)=0 " " Delta vec(P)_(y)=0 " " vec(P)_(yi)=vec(P)_(yf)`

`vec(P)_(yi)=0 " " therefore m_(1)vec(V)_(y_(1))+m_(2)vec(V)_(y_(2))=0, m_(1)vec(y)_(1)=-m_(2)vec(y)_(2)`
`y_(2)=-((cancel(m))/(4)xx15)/((3cancel(m))/(4))" " y_(2)=-5 cm`.
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