Home
Class 11
PHYSICS
A 75 kg man stands in a lift . What forc...

A 75 kg man stands in a lift . What force does the floor exert on him when the elevator starts moving upwards with an acceleration of ` 2 ms^(-2)` Given : `g=10ms^(-2)` .

Text Solution

Verified by Experts

`R-mg = ma`,
`R=mg+ma=m(g+a)`
`=75(10+2)N=900N`
`=(900)/(10)` kg wt. = 90 kg. wt
Promotional Banner

Similar Questions

Explore conceptually related problems

A 75kg man stands in a lift. What force does the floor exert on him when the elevator starts moving upward with an acceleration of 2 ms^(-2) Given: g = 10 ms^(-2) .

In a given figure the acceleration of M is (g=10ms^(-2))

The mass of man when standing on the lift is 60 kg. The weight when the lift is moving upwards with acceration 4.9 ms^(-2) is

A man of mass 40kg is standing on a weighting machine kept on the floor of an elevator which is moving up with an acceleration of 2m//s^2 Find the reading of the weighing maching.

A man of mass 40kg is standing on a weighting machine kept on the floor of an elevator which is moving up with an acceleration of 2m//s^2 Find the reading of the weighing maching.

A man of 60kg mass is in a lift. Find the apparent weight of the man when the lift is moving (a) up with uniform acceleration 4ms^(-2) (b) down with uniform acceleration of 2ms^(-2) ( g=10ms^(-2))

Calculate the work done in lifting a 300N weight to a height of 10m with an acceleration 0.5ms^(-2) . Take g= 10ms^(-2) .

A wooden block of mass 1kg and density 800 Kg m^(-3) is held stationery, with the help of a string, in a container filled with water of density 1000 kg m^(-3) as shown in the figure. If the container is moved upwards with an acceleration of 2 m s^(-2) , then the tension in the string will be ( take g=10ms^(-2) )

A man, of mass 60kg, is riding in a lift. The weights of the man, when the lift is acceleration upwards and downwards at 2ms^(-2) are respectively. (Taking g=10ms^(-2) )