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A horizontal converyor belt moves with a...

A horizontal converyor belt moves with a constant velocity V. A small block is projected with a velocity of 6 mis on it in a direction opposite to the direction of motion of the belt. The block comes to rest relative to the belt in a time 4s. `mu = 0.3 g, g= 10 m//s^(2)`
Find V

Text Solution

Verified by Experts

`|vec(V)_(b,c)|=V_(b)+V_(c )=6+V`
`f=mu mg = 0.3 xx m xx 10 = 3m`
Retardation a `= (3m)/(m)=3m//s^(2)`
`u_(r )=6+V, V_(r )= 0, t = 4` sec
`a_(r ) = - 3 ms^(-2)`
`V_(r )= u_(r )+a_(r )t`
`0=(6+V)-3xx4`
V = 6 m/s.
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