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Two blocks of masses'm' and 'M' are arra...

Two blocks of masses'm' and 'M' are arranged as shown in the figure. The coefficient of friction between the two blocks is ' `mu` ', where as between the lower block and the horizontal surface is zero. Find the force 'F' to be applied on the upper block, for the system to be under equilibrium ?

Text Solution

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On the upper block,
`F=T+f=T+mu N`
`F = T+mu mg " "` ………..(1)
On the lower block
`T = mu mg " "` …..(2)
from (1) and (2), we get, `F = 2 mu mg`
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