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A 30 kg block is to be moved up an incli...

A 30 kg block is to be moved up an inclined plane at an anglue 30° to the horizontal with a velocity of `5ms^(-1)`. If the frictional force retarding the motion is 150N find the horizontal force required to move the block up the plane. (`g=10ms^(-2)`)

Text Solution

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The force required to a body up an inclined plane is `F = mg sin theta +` frictional force
`= 30(10)sin 30^(@)+150=300 N`. If P is the horizontal force, `F = P cos theta`
`P=(F)/(cos theta)=(300)/(cos theta)=(300xx2)/(sqrt(3))`
`= 200 sqrt(3)=346 N`.
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