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A particle of mass m strikes a horizonta...

A particle of mass `m` strikes a horizontal smooth floor with velocity `u` making an angle `theta` with the floor and rebound with velocity `v` making an angle `theta` with the floor. The coefficient of restitution between the particle and the floor is `e`. Then

A

the impulse delivered by the floor to the body is mu(1+e) sin `theta`

B

`tan phi = e tan theta`

C

`v = usqrt(1-(1-e^(2))sin^(2) theta)`

D

the ratio of the final kinetic energy to the initial kinetic energy is `cos^(2) theta = e^(2) sin^(2) theta`

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A, B, D
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