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Let bara = bari + 2barj+ 3bark , barb = ...

Let `bara = bari + 2barj+ 3bark , barb = -bari + 2barj+bark. " If " barc = 3bari +barj+tbark` is perpendicular to `(bara+barb)`, then find t.

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Let's solve the problem step by step. ### Step 1: Define the vectors We are given the following vectors: - \( \vec{a} = \hat{i} + 2\hat{j} + 3\hat{k} \) - \( \vec{b} = -\hat{i} + 2\hat{j} + \hat{k} \) - \( \vec{c} = 3\hat{i} + \hat{j} + t\hat{k} \) ### Step 2: Calculate \( \vec{a} + \vec{b} \) Now, we need to find the sum of vectors \( \vec{a} \) and \( \vec{b} \): \[ \vec{a} + \vec{b} = (\hat{i} + 2\hat{j} + 3\hat{k}) + (-\hat{i} + 2\hat{j} + \hat{k}) \] Combining like terms: \[ = (1 - 1)\hat{i} + (2 + 2)\hat{j} + (3 + 1)\hat{k} = 0\hat{i} + 4\hat{j} + 4\hat{k} \] Thus, \[ \vec{a} + \vec{b} = 4\hat{j} + 4\hat{k} \] ### Step 3: Use the condition of perpendicularity Since \( \vec{c} \) is perpendicular to \( \vec{a} + \vec{b} \), we can use the dot product: \[ (\vec{a} + \vec{b}) \cdot \vec{c} = 0 \] Substituting the vectors: \[ (4\hat{j} + 4\hat{k}) \cdot (3\hat{i} + \hat{j} + t\hat{k}) = 0 \] ### Step 4: Calculate the dot product Now, we calculate the dot product: \[ = 4\hat{j} \cdot 3\hat{i} + 4\hat{j} \cdot \hat{j} + 4\hat{k} \cdot (t\hat{k}) \] Since \( \hat{i} \cdot \hat{j} = 0 \) and \( \hat{j} \cdot \hat{j} = 1 \) and \( \hat{k} \cdot \hat{k} = 1 \): \[ = 0 + 4 \cdot 1 + 4t \cdot 1 = 4 + 4t \] ### Step 5: Set the dot product equal to zero Setting the result equal to zero: \[ 4 + 4t = 0 \] ### Step 6: Solve for \( t \) Now, we solve for \( t \): \[ 4t = -4 \implies t = -1 \] ### Final Answer Thus, the value of \( t \) is: \[ \boxed{-1} \]
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