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Calculate the amount of KCl which must b...

Calculate the amount of `KCl` which must be added to `1kg` of water so that the freezing point is depressed by `2K`. (`K_(f)` for water `=1.86K kg "mol"^(-1)`).

Text Solution

Verified by Experts

Assuming `100%` dissociation of `KCl`,
`I = 2, DeltaT_(f) = 2K`
`K_(f) = 1.86 k kg mol^(-1)`
`W_(B) = ?`
`M_(B) = 74.5 gmol^(-1)`
`DeltaT_(f) = I xx K_(f) xx M`
`2 = 2 xx 1.86 xx ("mass of KCl")/(74.5) xx 1 = (2xx1.86 xx "mass of KCl")/(74.5)`
Mass of `KCl = (74.5)/(1.86) = 40.08 "gm"`.
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