Home
Class 12
CHEMISTRY
Draw the structrue and name the product ...

Draw the structrue and name the product formed if the following alcohols are oxidized. Assume that an excess of oxidising agent is used.
(i) `CH_(3)CH_(2)CH_(2)CH_(2)OH`
(ii) 2-butenol
(iii) 2-methyl-1-propanol

Text Solution

Verified by Experts

(i) `CH_(3)CH_(2)CH_(2)CH_(2)OH overset(K_(2)Cr_(2)O_(7)//H^(+))rarr underset("Butanoic acid")(CH_(3)CH_(2)CH_(2)COOH`
(ii) `CH_(2)-CH=Ch-overset(OH)overset(|)CH_(2)overset("PCC")underset("But-2en-lal")rarrCH_(3)-CH=CH-CHO`
(iii) `CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)OHoverset(K_(2)Cr_(2)O_(7)//H^(+))rarrunderset(2-"Methyl propanoic acid")(CH_(3)-underset(CH_(3))underset(|)(CH)-COOH)`
Promotional Banner

Topper's Solved these Questions

  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise SET-II|32 Videos
  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise SET-III|34 Videos
  • SAMPLE PAPER 2019

    XII BOARDS PREVIOUS YEAR|Exercise SECTION: D|1 Videos

Similar Questions

Explore conceptually related problems

The IUPAC name of CH_(3)-=C-CH_(2)-CH_(2)OH is

Arrange the following in decreasing order of boiling point. (i) CH_(3)CH_(2)CH_(2)CH_(2)OH (ii) CH_(3)CH_(2)OCH_(2)CH_(3) (iii) CH_(3)CH_(2)CH_(2)COOH

Which is the main product obtained when the following haloalkanes are treated with alcoholic KOH? (i). CH_(3)CH_(2)CHICH_(3) (ii). CH_(3)CH_(2)C(CH_(3))_(2)Br

Arrange the following in decreasing order of solubility in water (i) CH_(3)CH_(2)OH (ii) CH_(3)OH (iii) C_(6)H_(5)CH_(2)OH .

Arrange the following alcohols in order of increasing reactivity towards sodium metal. (i) CH_(3)OH (ii) (CH_(3))_(2)CH-OH (iii) CH_(3)CH_(2)OH (iv) (CH_(3))_(3)C-OH

Arrange the following alcohols in order of increasing reactivity towards sodium metal . (CH_(3))_(3) C- OH (ii) (CH_(3))_(2) CH - OH CH_(3)CH_(2)OH