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Centre of mass of two particle with mass...

Centre of mass of two particle with masses 2 kg and 1 kg locsted at (1, 0, 1) and (2, 2, 0) has the co - ordinates of

A

`(4)/(3),(2)/(3),(2)/(3)`

B

`(2)/(3),(4)/(3),(2)/(3)`

C

`(2)/(3),(2)/(3),(4)/(3)`

D

`(1)/(3),(2)/(3),(2)/(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the center of mass of two particles with given masses and coordinates, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the masses and their coordinates:** - Mass \( m_1 = 2 \, \text{kg} \) located at coordinates \( (x_1, y_1, z_1) = (1, 0, 1) \). - Mass \( m_2 = 1 \, \text{kg} \) located at coordinates \( (x_2, y_2, z_2) = (2, 2, 0) \). 2. **Use the formula for the center of mass (COM):** The coordinates of the center of mass \( (X_{cm}, Y_{cm}, Z_{cm}) \) can be calculated using the formula: \[ X_{cm} = \frac{m_1 x_1 + m_2 x_2}{m_1 + m_2} \] \[ Y_{cm} = \frac{m_1 y_1 + m_2 y_2}{m_1 + m_2} \] \[ Z_{cm} = \frac{m_1 z_1 + m_2 z_2}{m_1 + m_2} \] 3. **Calculate the total mass:** \[ m_{total} = m_1 + m_2 = 2 \, \text{kg} + 1 \, \text{kg} = 3 \, \text{kg} \] 4. **Calculate the \( X_{cm} \):** \[ X_{cm} = \frac{(2 \, \text{kg} \cdot 1) + (1 \, \text{kg} \cdot 2)}{3 \, \text{kg}} = \frac{2 + 2}{3} = \frac{4}{3} \] 5. **Calculate the \( Y_{cm} \):** \[ Y_{cm} = \frac{(2 \, \text{kg} \cdot 0) + (1 \, \text{kg} \cdot 2)}{3 \, \text{kg}} = \frac{0 + 2}{3} = \frac{2}{3} \] 6. **Calculate the \( Z_{cm} \):** \[ Z_{cm} = \frac{(2 \, \text{kg} \cdot 1) + (1 \, \text{kg} \cdot 0)}{3 \, \text{kg}} = \frac{2 + 0}{3} = \frac{2}{3} \] 7. **Write the final coordinates of the center of mass:** The coordinates of the center of mass are: \[ (X_{cm}, Y_{cm}, Z_{cm}) = \left(\frac{4}{3}, \frac{2}{3}, \frac{2}{3}\right) \] ### Final Answer: The coordinates of the center of mass are \( \left(\frac{4}{3}, \frac{2}{3}, \frac{2}{3}\right) \).
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