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Two particles of masses `1 kg` and `3 kg` move towards each other under mutual force of attraction. No other force acts on them. When the relative velocity of approach of the two particles is `2 m//s`. their centre of mass has a velocity of `0.5 m//s`. When the relative velocity of approach becomes `3 m//s`, the velocity of the centre of mass is `0.75 m//s`.

A

`0.75ms^(-1)`

B

`0.5ms^(-1)`

C

`2.5ms^(-1)`

D

`0ms^(-1)`

Text Solution

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The correct Answer is:
B
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