The percentage errors in the measurement of mass and speed are `2%` and `3%` respectively. The error in kinetic energy obtained by measuring mass and speed, will be

Explanation

`(Delta m)/(m) xx 100= 2%, (Delta v)/(v) xx 100= 3%`
Kinetic energy `E= (1)/(2) mv^(2)`
Maximum error in kinetic energy
`(Delta E)/(E )xx 100= (Delta m)/(m) xx 100 + 2 (Delta v)/(v) xx 100`
Maximum error in kinetic energy
`=2% + 2 xx 3% = 2 % + 6% = 8%`