Home
Class 11
PHYSICS
Solve with due regard to significant fig...

Solve with due regard to significant figures.
(i) `46.7 - 10.4 = " "` (ii) `(3.0 xx 10^(-8)) + (4.5 xx 10^(-6)) = `

Text Solution

Verified by Experts

(i) 46.7- 10.04
Here 46.7 has one decimal place, and 10.04 has two decimal places.
`therefore 46.7-10.04= 36.66`
The result should have only one decimal place. The result is 36.7
(ii) `3.0 xx 10^(-8) + 4.5 xx 10^(-6)`
`=0.03 xx 10^(-6) + 4.5 xx 10^(-6)`
`=4.53 xx 10^(-6)`
Here `4.5 xx 10^(-6)` has only one decimal place and `0.03 xx 10^(-6)` can have two decimal places. This result should be rounded off to one decimal place.
`therefore (3.0 xx 10^(-8)) + (4.5 xx 10^(-6))= 4.5 xx 10^(-6)`
Promotional Banner

Similar Questions

Explore conceptually related problems

Solve with due regard to significant figure. 46.7 -10.04 =

Solve with due regards to significant figures 4.0 xx (10^-4) - 2.5 xx 10^(-6) .

Solve with due regard to significant figures: ( 5.42 xx 0.6753)/( 0.085)

Solve with due regard to significant figure. (3.0 xx10^(-8))+ (4.5 xx 10^(-6)) =

Number of significant figures in 6.62 xx 10^(-34)

The sum of the given two numbers with regard to significant figures is (5.0 xx 10^(-8)) + (4.5 xx 10^(-6)) =

Show with regards to significant figure (i) 908 + 2.76 (ii) 999-989 (iii) 4.0 xx 10^(4) - 2.5 xx 10^(2) (iv) 4.0 xx 10^(4) - 2.5 xx 10^(5) (v) 6.75 xx 10^(3) + 4.52 xx 10^(2) (vi) 625 + 125

Find the number of significant figures in the 4.51 xx 10^8

The value of 42 xx 0.041 with due regard to significant figures is

Give the number of significant figures 2.653xx10^(4)