The mass of 1.2 cm 3 of a certain substance is 5.74 g. calculate its density with due regard to significant figures.

Explanation

Mass, m= 5.74g, volume, v= `1.2 cm^(3)`
density, `d= (m)/(v) = (5.74g)/(1.2 cm^(3))`
5.74 has significant digits and 1.2 has two significant digits.
no need for rounding off,
`therefore d = (5.74)/(1.2)= 4.783333`. This is to be rounded off to two significant digits. The density of the given substance is `4.783 = 4.8 g cm^(-3)`