Home
Class 11
PHYSICS
If L1 = 2.02 m pm 0.01 m , L2 = 1.02 m p...

If `L_1 = 2.02 m pm 0.01 m , L_2 = 1.02 m pm 0.01 m , ` determine `L_1 + 2L_2`

A

`4.06 +- 0.02`

B

`4.06 +- 0.03`

C

`4.06 +- 0.005`

D

`4.06 +- 0.01`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

If L = 2.01 m pm 0.01 m , what is 3 L ?

If L = (20 pm 0.01) m and B = (10 pm 0.02)m then L/B is

If L = 20.04 m pm 0.01 m , B= 2.52 m pm 0.02 m . What are the values of (L xx B) and (L+B) ?

If L = 20.04 m pm 0.01 m , B= 2.52 m pm 0.02 m . What are the values of (L xx B) and (L+B) ?

If L = 2.06 cm pm 0.02 cm , B = 1.11 cm pm 0.03 cm . What are (L+B) and (L-B) equal to ?

If L = (2 pm 0.01) m and B = (1 pm 0.02)m then L/B is

If l_(1) = (10.0 pm 0.1) cm and l_(2) = (9.0 pm 0.1) cm , find the their sum , difference and error in each .

If L=20.04m pm 0.01m, B=2.52 m pm 0.02 m. The value of (LxxB) is

The line l_1 x+ m_1 y+n=0 and l_2 x + m_2 y+n=0 will cut the coordinate axes at concyclic points if (A) l_1 m_1 = l_2 m_2 (B) l_1 m_2 = l_2 m_1 (C) l_1 l_2 = m_1 m_2 (D) l_1 l_2 m_1 m_2 = n^2

Mass and lengh of a metal cube are "10 kg "pm" 0.01 kg and 1 m "pm" 0.02 m" . Its density with percentage then percentage error is