Home
Class 11
PHYSICS
The speed of a train increases at a cons...

The speed of a train increases at a constant rate `alpha` from zero to v and then remains constant for an interval and finally decreases to zero at a constant rate `beta`. The total distance travelled by the train is l. The time taken to complete the journey is t. Then,

A

`t = l/v + v/2 ( 1/alpha + 1/beta)`

B

`t = l/v - v/2 (1/alpha + 1/beta)`

C

`t= l/v - v/2 ( 1/alpha - 1/beta)`

D

`t = l/v + v/2 (1/alpha - 1/beta)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

A train accelerates from rest at a constant rate alpha for some time and then it retards to rest at the constant rate beta . If the total distance covered by the train is s, then the velocity of the train is

The speed of a car increases uniformly from zero to 10ms^-1 in 2s and then remains constant (figure) a. Find the distance travelled by the car in the first two seconds. b. Find the distance travelled by the car in the next two seconds. c. Find the total distance travelled in 4s .

A car, starting from rest, accelerates at the rate f through a distance s, then continues at constant speed for time t and then decelerates at the rate f/ 2 to come to rest. If the total distance travelled is 15 s, then

A car, starting from rest, accelerates at the rate f through a distance s, then continues at constant speed for time t and then decelerates at the rate f/ 2 to come to rest. If the total distance travelled is 15 s, then

A bus starting from rest, accelerates at the rate of f through a distance S, then continues at constant speed for time t and declerates at the rate f/2 to come to rest. If the total distance travelled is 15 S then S =

A train accelerates from rest at a constant rate a for time t_(1) and then it retards at the constant rate b for time t_(2) then comes to rest. Find the ratio t_(1) / t_(2) .

A car accelerates from rest at a constant rate 'alpha' for some time after which it decelerates at a constant rate beta to come to rest. If the total time elapsed is t, the maximum velocity acquired by the car is given by :

A lift ascends with constant acceleration a=1ms^(-2) , then with constant velocity and finally, it stops under constant retardation a=1ms^(-2) . If total distance ascended by the lift is 7 m, in a total time of the journey is 8 s. Find the time (in second) for which lift moves with constant velocity.

A particle, starting from rest, moves in a straight line with constant acceleration a_0 for a time interval t_0 .Then is accelerates at a constant rate 2a_0 for time interval 2t_0 .The distance travelled by the particle in time 3t_0 from the starts is S . Then (S)/(a_0t_0^(2) )=

A train travels at a constant rate. If the train takes 13 minutes to travel m kilometers, how long will the train take to travel n kilometers?