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From the top of a tower, a stone is thro...

From the top of a tower, a stone is thrown up and reaches the ground in time `t_(1)=9`s. a second stone is thrown down with the same speed and reaches the ground in time `t_(2)=4s`. A third stone is released from rest and reaches the ground in time `t_(3)`, which is equal to

A

`t_(3)=t_(1)+t_(2)`

B

`t_(3) =sqrt(t_(1)t_(2))`

C

`t_(3)=(t_(1)+t_(2))/(2)`

D

`t_(3)=t_(1)-t_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
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