Home
Class 12
PHYSICS
In the given Boolean expression, Y=A.bar...

In the given Boolean expression, `Y=A.bar(B)+B.barA`, if A=1, B=1 then Y will be

A

0

B

1

C

11

D

10

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • SEMICONDUCTOR DEVICES

    AAKASH SERIES|Exercise EXERCISE - III|3 Videos

  • SEMICONDUCTOR DEVICES

    AAKASH SERIES|Exercise EXERCISE - IB|7 Videos

  • RAY OPTICS

    AAKASH SERIES|Exercise PROBLEMS ( LEVEL-II)|60 Videos

  • UNITS AND MEASUREMENT

    AAKASH SERIES|Exercise PRACTICE EXERCISE|45 Videos

Similar Questions

Explore conceptually related problems

What will be the input of A and B for the Boolean expression bar((A+B)).bar((A.B))=1 ?

In the Boolean algebra bar(A).bar(B) equals

The Boolean expression for the given circuit is

Name the gate , which represents the Boolean expression y = A. B for inputs A, B

An AND gate is following by a NOT gate in series. With two inputs A & B , the Boolean expression for the out put Y will be :

In boolean algebra, if A=1 and B=0 then the value of A+barB is

The Boolean expression for the output Y of the logic operation shown is-

If A = 1 and B = 0, then in terms of Boolean algebra , A + bar(B) = .

bar(A.barB+barA.B) is equivalent to

The Boolean expression of the output y in terms of the input A and B for the circuit shown in figure.