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Two particles A and B are thrown vertica...

Two particles `A` and `B` are thrown vertically upward with velocity, `5 m s^(-1)` and `10 m s^(-1)` respectively `(g=10 m s^(-2))`, Find separation between them after `1 s`.
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Text Solution

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`S_(A)= ut-1/2"gt"^(2)=5t-1/2xx10xxt^(2)=5xx1-5xx1^(2)=5-5=0`
`S_(B)=ut-1/2"gt"^(2)=10xx1-1/2xx10xx1^(2)=10-5=5`
`:.S_(B)-S_(A)`=separation`=5m`.
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