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Two particles A and B are projected ...

Two particles A and B are projected in air .A is thrown horizontally .B is thrown vertically up . What is the separation between them after 1 sec .

Text Solution

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`veca_(AB)=veca_(A)-veca_(B)=0`
`vecV_(AB)=sqrt(10^(2)+10^(2))=10sqrt2`
`:. S_(AB)=V_(AB)`
`t=(10sqrt(2)) t=10sqrt(2)m`
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