A force` 3hati+2hatj+hatk` newtons acts on aa body which is initially at rest. At the end of 10 seconds the velocity of the body is `2hati+2hatj-2hatk m//s`. What is the mass of the body?

A force (2hati+3hatj-hatk) newtons acts on a particle having position vector (hati-hatj+2hatk) . Find the torque of the force about origin.

A force ( 5hati + 2hatj - 5hatk) newtons acts on a particle on a particle having postions vectors ( hati - 2hatj + hatk) .find the torque of the force about the origin .

A body of mass 5kg moves under a force of 10hati+10hatj-20hatk . What is the acceleration produced?

A Force F = (2 hati + hatj + 3 hatk) N acts on a particle of mass 1 kg for 2 s . If initial velocity of particle is u = (2 hati + hatj) m/s . Speed of particle at the end of 2 s will be

A force vecF=(6hati-8hatj+10hatk)N produces acceleration of 1 ms^(-2) in a body. Calculate the mass of the body.

A force F=(2hati+3hatj-2hatk)N is acting on a body at point (2m, 4m,-2m) . Find torque of this force about origin.

A force (4hati+hatj-2hatk) N acting on a body maintains its velocity at (2hati+2hatj+3hatk) m s^(-1) . The power exerted is

A force 2hati+3hatj+4hatk N acts on a body for 4 sec, produces a displacement of (3hati+4hatj+5hatk) m. the power used is

A force F=(6hati-8hatj+10hatk) N produces acceleration of sqrt(2) ms^(-2) in a body. Calculate the mass of the body.

Two forces -hati+2hatj-hatk and 2hati-5hatj+6hatk act on a particfle whose position vector is 4hati-3hatj+2hatk and displace it to another point whose positon vector is 6hati+hatj-3hatk . Find the total work done by the force.