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If a planet of mass .m. is revolving aro...

If a planet of mass .m. is revolving around the sun in a circular orbit of radius .r. with time period T, then the mass of the sun is

A

`(4pi^(2)r^(3))/(GT) `

B

`(4pi^(2)r^(3))/(GT^(2))`

C

`(4pi^(2)r)/(GT)`

D

`(4pi^(2)r^(3))/(G^(2)T^(2)) `

Text Solution

AI Generated Solution

The correct Answer is:
To find the mass of the sun (Ms) given that a planet of mass (m) is revolving around it in a circular orbit of radius (r) with a time period (T), we can follow these steps: ### Step 1: Identify the Forces Acting on the Planet The planet experiences two main forces: 1. **Centripetal Force (Fc)**: This is required to keep the planet in circular motion. 2. **Gravitational Force (Fg)**: This is the attractive force between the planet and the sun. ### Step 2: Write the Expression for Centripetal Force The centripetal force required for circular motion is given by: \[ F_c = \frac{m v^2}{r} \] where \(v\) is the orbital speed of the planet. ### Step 3: Relate Orbital Speed to Time Period The orbital speed \(v\) can be expressed in terms of the radius \(r\) and the time period \(T\): \[ v = \frac{2\pi r}{T} \] Substituting this into the centripetal force equation gives: \[ F_c = \frac{m \left(\frac{2\pi r}{T}\right)^2}{r} = \frac{m (4\pi^2 r)}{T^2} \] ### Step 4: Write the Expression for Gravitational Force The gravitational force acting on the planet due to the sun is given by Newton's law of gravitation: \[ F_g = \frac{G M_s m}{r^2} \] where \(G\) is the gravitational constant and \(M_s\) is the mass of the sun. ### Step 5: Set the Forces Equal Since the centripetal force is provided by the gravitational force, we can set these two expressions equal to each other: \[ \frac{m (4\pi^2 r)}{T^2} = \frac{G M_s m}{r^2} \] ### Step 6: Simplify the Equation We can cancel \(m\) from both sides (assuming \(m \neq 0\)): \[ \frac{4\pi^2 r}{T^2} = \frac{G M_s}{r^2} \] ### Step 7: Solve for the Mass of the Sun Rearranging the equation to solve for \(M_s\): \[ M_s = \frac{4\pi^2 r^3}{G T^2} \] ### Final Answer Thus, the mass of the sun is given by: \[ M_s = \frac{4\pi^2 r^3}{G T^2} \] ---
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