Home
Class 11
PHYSICS
The gravitational potential due to a mas...

The gravitational potential due to a mass distribution is `V=A/sqrt(x^2+a^2)`. Find the gravitational field.

A

`(Ay)/((x^(2) + a^(2))^(1//2))` in the x-direction

B

`(Ax)/((x^(2) + a^(2))^(3//2))` in x-direction

C

`A(x^(2) + a^(2))` in y-direction

D

2xA in z-direction

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

The gravitational potential due to a mass distribution is V = 3X^(2) Y+ Y^(3) Z . Find the gravitational filed.

The gravitational potential due to a mass distrubution is given by V=(8x)/(x^(2)+p^(2)) . Find gravitational field at x = p.

Define gravitational potential and its unit.

The gravitational potential energy is maximum at :

On the x - axis and at a distance x from the origin, the gravitational field due to a mass distribution is given by (Ax)/((x^2+a^2)^(3//2)) in the x - direction. The magnitude of gravitational potential on the x - axis at a distance x, taking its value to be zero at infinity , is :

The gravitational potential in a region by V = (20x + 40y)j/kg. Find out the gravitational field (in newton /kg) at a point co-ordinates (2,4). Also find out the magnitude of the gravitational force on a particle of 0.250 kg placed at the point (2,4) .

Gravitational field due to a solid sphere

The gravitational potential due to earth at infinite distance from it is zero. Let the gravitational potential at a point P be -5 J kg^(-1) . Suppose, we arbitrarily assume the gravitational potential at infinity to be +10 J kg^(-1) , then the gravitational potential at P will be

The gravitational field due to a mass distribution is E=(A)/(x^(2)) in x-direction. Here, A is a constant, Taking the gravitational potential to be zero at infinity, potential at x is