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Velocity of a particle moving in a strai...

Velocity of a particle moving in a straight line varies with its displacement as `v=(sqrt(4 +4s))m//s.` Displacement of particle at time `t =0` is `s = 0`. Find displacement of particle at time `t=2 s`.

Text Solution

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Squaring the given equation, we get `v^(2)=4+4s`
Now , comparing it with `v^(2)=u^(2)+2as`
we get, `u=2m//s "and" a=2m//s^(2)`
therefore , Dispalcement `t=2s`is
`s=ut+1/2at^(2)"or"s=(2)(2)+1/2(2)(2)^(2)"or"s=8m`
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